For which values of A, B, and C will Ax + By = C be a horizontal line through the point (−4, 2)? �� A = 1, B = 0, C = 2
�� A = 1, B = 0, C = −4
�� A = 0, B = 1, C = 2
�� A = 0, B = 1, C = −4

Simple, if you you want a perfectly flat line, then simply have A = 0, B = 1, and C = 2, and vuala. It is done.

But if you want any line that isn’t perpendicular to the x-axis, then, it’s again, simple. Just find the slope between the point (-4, 2) and any point on the y-axis.

Which will be,

y = mx + b

m = slope, m = (y2 - y1)/(x2 - x1), b = y-intercept, (p, 0) = arbitrary point on the y-axis

m = (2 - p)/(-4 - 0) = (2 - p)/-4 = (2 - p)/-4

y = ((2 - p)/-4)x + p

Step-by-step explanation:

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363