Pq has a length of 17 units with p(-4,7). If the x and y coordinates of q are both greater than the x and y coordinates of p what are possible integer value coordinates of q

Step-by-step explanation:

1²+16²=1+256=257≠289(17²)

2²+16²=4+256=260≠17²

3²+16²=9+256=265≠17²

4²+16²=16+256=272≠17²

5²+16²=25+256=281≠17²

6²+16²=36+256=292>17²

6²+15²=36+225=261≠17²

7²+15²=49+225=274≠17²

8²+15²=64+225=289=17²

9²+14²=81+196=277≠17²

10²+14^2=100+196>289

10²+13²=100+169=269≠17²

11²+13³=121+169=290>17²

11²+12²=121+144=265≠17²

12²+12²=144+144=288≠17²

so only integer values are 8²+15²=17²

(x+4)²+(y-7)²=17²

if x+4=8

x=8-4=4

y-7=15

y=15+7=22

so q is (4,22)

if x+4=15

x=15-4=11

y-7=8

y=8+7=15

point is (11,15)

step-by-step explanation:

1. minimum

2. 6400

3. eight

hope this !