If we have a group of 5 men and 4 women and we select two at random, without replacement, then find the probability that one of each gender is selected

Step-by-step explanation:

If we have a group of 5 men and 4 women, the total number of people we have is 5+4 = 9 people

Total outcome = 9people

For us to select one of each gender without replacement and selecting two at random means we can select a male before a female or a female before a male.

Let W =Women and M = Male

The Probability of selecting two at random without repalcement is given as;

= Pr(W)Pr(M) + Pr(M)Pr(W)

= (4/9*5/8)+(5/9*4/8) (Note that the total number reduces by 1 during the second pick since we aren't replacing the person we picked first)

= 20/72 + 20/72

= 40/72

= 20/36

= 5/9

Hence the the probability that one of each gender is selected is 5/9

step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without

it is only things thain can be deafeated

step-by-step explanation: