Find the distance points p (3,6) and q (7,3) to the nearest tenth?

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One method is to plot the points P(3,6) and Q(7,3) on the same xy grid.  Plot a third point R at (3,3). See the diagram below.

A right triangle forms in which we can find the legs PR = 3 and RQ = 4. The hypotenuse is found through the pythagorean theorem.

a^2+b^2=c^2

3^2+4^2 = c^2

9+16 = c^2

c^2 = 25

c = sqrt(25)

c = 5

This is the length of PQ

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Or you can use the distance formula which is effectively using the pythagorean theorem just in a slightly different format (though it may not be obvious).

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.