20 years ago the age of father was 5 times the age of his son. at peesent father's age is 10 years more than twice his sons. find theur present ages URGENT FAST HELP PLEASE

Step-by-step explanation:

At present:

Let son's age = x

Father's age = 2x + 10

Before 20 years:

son's age = x - 20

Father's age = 2x + 10 - 20 = 2x - 10

Father's age = 5 * (Son's age)

         2x - 10 = 5*(x - 20)

        2x - 10 = 5x - 100 {add 100 to both sides}

2x -10 + 100 = 5x - 100 +100

     2x  + 90 = 5x            {Subtract  2x from both sides}

2x + 90 - 2x = 5x- 2x

             90  = 3x               {divide both sides by 3}

          90/3 = x

x = 30

Present age of :

Son = 30 years

Father = 2*30 +10 = 60 + 10

           = 70 years

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.