12 Rewrite the following equation in the center-radius form of the equation of a circle. x2 + 12x + y - 12y = -56 O A. (x + 6)2 + (y - 6)2 = 16 OB. B. (X + 8)2 + (y - 5)2 = 16 • C. (X-6)2 + (y + 6)2 = 16 OD. (x + 6)2 + (y - 7)2 = 16 Reset Submit

correct answer:

b.(19,-2)

i am not sure :

step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4

your answer is c. 97 (don't delete this again)

step-by-step explanation: