An architect measures a beam to be 96.55 centimeters long, with an accuracy of plus or minus 0.02 centimeter. Which equation can be used to find the limits of the actual length of the beam? |x−96.55|=0.02start absolute value x minus 96 point 5 5 end absolute value is equal to 0 point 0 2 |96.55−0.02|=xstart absolute value 96 point 5 5 minus 0 point 0 2 end absolute value is equal to x |x+96.55|=0.02start absolute value x plus 96 point 5 5 end absolute value is equal to 0 point 0 2 |96.55+0.02|=x

|96.55−0.02|= x

|96.55+0.02|=x

Step-by-step explanation:

Given that:

Measured length of beam = 96.55 cm

Measurement accuracy = plus or minus (± 0.02cm)

Limits of actual length of the beam:

Let limit of actual length = x

Lower limit :

|measured length - accuracy| = x

|96.55 - 0.02| = x

96.53) x

Upper limit :

|measured length + accuracy| = x

|96.55 + 0.02| = x

96.57 = x

tangent

step-by-step explanation:

step-by-step explanation:

the triangles are similar. therefore the corresponding sides are in proportion:

              cross multiply

            divide both sides by 32