You pay $14.82 for 1.5 pounds of ham. You buy 2.25 pounds of roast beef for $12.40 per pound. a. How much less does ham cost per pound than roast beef? $ less per pound b. How much more do you spend on roast beef than on ham? $

A.) $2.52 less per pound. B.) $13.08 more

Step-by-step explanation:

A.) You pay $14.82 for 1.5 lbs of ham. You divide $14.82 by 1.5 lbs (14.82/1.5) to figure out how much you spend per pound of ham. You should get $9.88. Since you spend $12.40 per pound of roast beef, you subtract $9.88 from $12.40 ($12.40 - $9.88). You should get $2.52, which is your answer.

B.) Since you paid $14.82 for 1.5 lbs of ham, you already have this variable. Take the 2.25 lbs of roast beef and multiply it by $12.40 per pound (12.40*2.25). You then take that number ($27.90) and subtract it by $14.82 (27.90-14.82) and you should get your answer, $13.08.

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)