Mathematics, 07.10.2020 22:01 warnene17
A certain restaurant always overbooks. If possible. At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53. If the probability of a party not showing up is 0.04, assuming independence, what is the probability that the restaurant can coommodate all the customers who do show up? You must show all of your work including the correct formulas for calculation to receive full credit of this answer
Answers: 2
![P(X\leq 50)=1-P(X50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564](/tpl/images/0793/3359/77025.png)
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A certain restaurant always overbooks. If possible. At 7:00 pm the restaurant can seat 50 parties, b...
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