WidgCo is a company that produces and sells widgets. Let p denote the price per widget (measured in dollars), and let x be the monthly demand for widgets. WidgCo's marketing department determines that p and x are related by the following demand equation: p(x) = 211 − 5x. The cost of producing x widgets is given by C(x) = 1,401 + 16x. Construct the revenue function, R(x). Find the production level that will result in the maximum revenue. Find the maximum monthly revenue. Enter your answer to part c in the box below. Round your answer to the nearest cent.

the revenue function = x · P(x) - C(x) = x · (211 − 5x) - (1,401 + 16x) = 211x - 5x² - 1,401 - 16x = -5x² + 211x - 16x - 1,401

R(x) = -5x² + 195x - 1,401

maximum revenue will be obtained for R'(x)

R'(x) = 2 · -5x + 195 = -10x + 195 = 0

195 = 10x

x = 19.5

the production level that yields a maximum profit should be 19.5

maximum monthly revenue

R(x) = -5·19.5² + 195·19.5 - 1,401 = -1,901.25 + 3,802.50 - 1,401 = $500.25

two data sets with the same median will not have the same varaibility

step-by-step explanation:

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column