Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of \$65$65dollar sign, 65 along with an hourly rate of \$28$28dollar sign, 28. The plumber only charges for a whole number of hours. Anand would like to spend no more than \$250$250dollar sign, 250, and he wonders how many hours of work he can afford.

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Complete Question

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an

hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford.

Let H represent the whole number of hours that the plumber works.

1) Which inequality describes this scenario?

Choose 1

A. 28 + 65H < 250

B. 28 + 65H > 250

C. 65 + 28H < 250

D. 65 +28H > 250

2) What is the largest whole number of hours that Anand can afford?

1) C. 65 + 28H < 250

2) 6 hours

Step-by-step explanation:

We are told in the question that:

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an

hourly rate of $28. The plumber only charges for a whole number of hours.

Hences we have:

$65 + 28 × H

We are told that:

Anand would like to spend no more than $250,

Hence,our equation becomes:

$65 + 28H ≤ $250

Where H = Hourly rates of the plumber.

1) Which inequality describes this scenario?

From the given options and our calculations above, Option C) 65 + 28H < 250 is the correct answer

2) What is the largest whole number of hours that Anand can afford?

We would use our equation above to solve for this.

65 + 28H < 250

= 65 + 28H ≤ 250

We convert or inequality sign to equal to sign

= 65 + 28H = 250

28H = 250 - 65

28H = 185

H = 185/28

H = 6.6071428571 hours

Therefore, the largest whole number of hours that Anand can afford is 6 hours

its d. the first coordintaes are 10,32

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.