Write the equation of the line that has a slope of 2 and passes through the point (-3,4)

2x - y - 11 = 0

Step-by-step explanation:

slope (m) = 2

(x1 ,y1) = (-3 ,4)

Equation of the line is ,

y - y1 = m ( x - x1 )

y - (-3) = 2 (x - 4)

y + 3 = 2x - 8

2x - 8 = y + 3

2x - y - 8 - 3 = 0

2x - y - 11 = 0 ,which is the required equation .

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: