Mathematics, 08.10.2020 04:01 lizzyhearts

Use appropriate descriptive statistics to summarize the transmission failure data. 2. Develop a 95% confidence interval for the mean number of miles driven until transmission failure for the population of automobiles with transmission failure. Provide a managerial interpretation of the interval estimate. 3. Discuss the implication of your statistical findings in terms of the belief that some owners of the automobiles experienced early transmission failures. 4. How many repair records should be sampled if the research firm

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Answer from: darriancascioli

Hello your question is incomplete below is the missing part of the question

Metropolitan Research, Inc., a consumer research organization, conducts surveys designed to evaluate a wide variety of products and services available to consumers. In one particular study, Metropolitan looked at consumer satisfaction with the performance of automobiles produced by a major Detroit manufacturer. A questionnaire sent to owners of one of the manufacturer's full-sized cars reviewed several complaints about early transmission problems. To learn more about the transmission failures, Metropolitan used a sample of actual transmission repairs provided by a transmission repair firm in the Detroit area. The following data show the actual number of miles driven for 50 vehicles at the time of transmission failure:

Miles

85092

39323

64342

74276

74425

37831

77539

32609

89641

61978

66998

67202

89341

88798

59465

94219

67998

40001

118444

73341

77437

116803

59817

72069

53500

85288

32534

92857

101769

25066

79294

138114

64090

63436

95774

77098

64544

53402

32464

65605

121352

69922

86813

85586

59902

85861

69568

35662

116269

82256

4.) How many repair records should be sampled if the research firm wants the population mean number of miles driven until transmission failure to be estimated with a margin of error of 5000 miles? Use 95% confidence.

answer : 1) Min value = 25070 1st quarter = 60420,Median = 72700,Mean = 73340,3rd quarter = 86580,Max value = 138100

2) ( 66438.73, 80241.87 )

3) The statistical results shows that some owners of the automobiles experienced early transmission failures

4) 95

Step-by-step explanation:

1) The transmission failure ( using descriptive statistics )

Min = 25070

1st quarter = 60420

Median = 72700

Mean = 73340

3rd quarter = 86580

Max = 138100

2) managerial interpretation of interval estimate

given 95% confidence interval

a = 0.05

z(0.025) = 1.96

Hence the 95% confidence interval for the mean number of miles driven until transmission failure

= xbar +/- Z*s/vn

⇒ 73340.3 +/- 1.96*24898.72 * $\sqrt{50}$

= ( 66438.73, 80241.87 )

3) The findings shows that some owners of the automobiles experienced early transmission failures

4 ) number of repair records

n = ( Z * S/E) ^2 ------- 1

Where : Z = 1.96, S = 24898.72, E = 5000

= 1.96 * 24898.72 / 5000 ) ^2

= 95

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