The Institute of Education Sciences measures the high school dropout rate as the percentage of 16- through 24-year-olds who are not enrolled in school and have not earned a high school credential. Last year, the high school dropout rate was 8.1%. A polling company recently took a survey of 1,000 people between the ages of 16 and 24 and found that 6.5% of them are high school dropouts. The polling company would like to determine whether the dropout rate has decreased. At a 5% significance level, the decision is to .

Step-by-step explanation:

Given that:

The population proportion = 8.1% = 0.081

Sample size = 1000

The sample proportion = 6.5%  = 0.065

The null and the alternative hypothesis for these studies can be computed as:

Since is not equal to the population proportion; then this is a two-tailed test.

The level of significance is given as 5% = 0.05

The standard error of the sample proportion can be computed as:

The z score test statistic is calculated as:

z = −1.860

For a two-tailed test, the p-value =

p-value = 2 × 0.0314

p-value = 0.0628

Rejection Criteria: To reject ; if the p-value is less than the level of significance ∝

The decision rule: We failed to reject the null hypothesis since the p-value is greater than the level of significance ∝.

Thus, there is insufficient evidence to conclude that p is not equal to 0.081

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6