If p(x)=2(x^2+1)+16, what is the value of p(12)?

Step-by-step explanation:

Hey there!

Given;

p(x)= 2(x^2+1)+16

And p(x)= 12

Now,

Putting value of p(12) in p(x)= 2(x^2+1)+16.

Therefore p(12)= 306.

Hope it helps...

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2