What is the solution to the equation 4 + 3sqrt 2y = 6?

4+3√2y = 6

3√2y = -4+6

3√2y = 2

(3√2y)2 = (2)2

18y = 4

Add 4 to both sides

18y = 4

Divide both sides by 18

A possible solution is :

y = (2/9)

y=2/9

Step-by-step explanation:

4+3√2y=6

3√2y+4=6

Step 1: Add -4 to both sides.

3√2y+4+−4=6+−4

3√2y=2

you would need to know all the numbers that are on there

step-by-step explanation: