What is the solution set to log8(4x + 2) + 4 ≥ 5? A. (–0.5, ∞)
B. [1.5, ∞)
C. (1.5, ∞)
D. [5, ∞)

 B) [1.5, ∞)

Step-by-step explanation:

log₈ (4x + 2) + 4 ≥ 5

log₈ (4x + 2)       ≥ 1               subtract 1 from both sides

       4x + 2         ≥ 8¹             apply log rules

       4x               ≥ 6              subtracted 2 from both sides

                       x ≥ 1.5            divided 4 from both sides

In interval notation:   [1.5, ∞)

1.5 is included so use the bracket.

It is "greater than" so it goes to infinity (which uses a parenthesis)

x=0

step-by-step explanation: