You place a cup of 200of coffee on a table in a room that is 67of, and 10 minutes later, it is 195of. approximately how long will it be before the coffee is 180of? use newton's law of cooling:

After 50.4 min.

Step-by-step explanation:

Newton's law of cooling-

where,

= the initial temp. = 200° F

k = 0.1947,

= 180° F

= 67° F

Putting the values,

y=mx+b is the final answer!   : )

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3