Anya found the slope of the line that passes through the points (–7, 4) and (2, –3). Her work is shown below. Let (x2, y2) be (–7, 4) and (x1, y1) be (2, –3).
m = m equals StartFraction x 2 minus x 1 over y 2 minus y 1.
= Equals StartFraction negative 7 minus 2 Over 4 minus negative 3.
= Negative StartFraction 9 Over 7 EndFraction.
The slope is Negative StartFraction 9 Over 7 EndFraction..
What error did she make?
She simplified the denominator incorrectly. The denominator simplifies to –7.
She labeled the points incorrectly. The point (–7, 4) should be (x1, y1).
She used an incorrect formula. The formula should be the change in y-values with respect to the change in the x-values.
She used an incorrect formula. The formula should be the sum of the x-values with respect to the sum of the y-values.

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

where r the answers

step-by-step explanation: