Problem 2: The perimeter of a rectangle is 72 meters. The width of the rectangle is 4 meters less than its length.
Part A: Which equation could be used to find the width and length of the
rectangle?
A. 1 + ((-4) = 72
C. (+2(e- 4) = 72
B. 21+ 2(1 - 4) = 72
D. 21 + ((-4) = 72

Deepak plotted these points on the number line. point a: –0.3 point b: – 3 4 point c: – 11 4 point d: –0.7 which point did he plot incorrectly?

What’s the range cuz i can’t find it?

Exercise: counting committees 0.0/2.0 puntos (calificable) we start with a pool of n people. a chaired committee consists of k≥1 members, out of whom one member is designated as the chairperson. the expression k(nk) can be interpreted as the number of possible chaired committees with k members. this is because we have (nk) choices for the k members, and once the members are chosen, there are then k choices for the chairperson. thus, c=∑k=1nk(nk) is the total number of possible chaired committees of any size. find the value of c (as a function of n ) by thinking about a different way of forming a chaired committee: first choose the chairperson, then choose the other members of the committee. the answer is of the form c=(α+nβ)2γn+δ. what are the values of α , β , γ , and δ ?