P(x)=x^4−3x^2+kx−2 where k is an unknown integer P(x) divided by (x−2) has a remainder of 10.
What is the value of k?

k = 4

Step-by-step explanation:

p(2) = (2)^4- 3(2)^2 +k(2) -2 = 10

16 - 12 - 2 + 2k = 10

2 +2k = 10

2k = 10 - 2 = 8

k = 4

the answer is b.)

< 1=< 2