Complete the equation for the standard form of the line that has an x-intercept of –4 and a y-intercept of 3. I asked this before but I still didn't get the answer that I wanted. :(

3x - 4y = -12

Step-by-step explanation:

Intercept form is x/a + y/b = 1, where a is the x-intercept and b is the y-intercept. From the question we have:

x-intercept = -4   (a = -4)

y-intercept = 3     (b = 3)

So we can plug this into the intercept form equation:

x/a + y/b = 1

x/-4 + y/3 = 1      

(The LCM of -4 and 3 is -4x3 = -12, so we can multiply both sides of the equation by -12 to get rid of the denominators)

-12x/-4 + -12y/3 = -12    (Cancelling)

         3x + (-4y) = -12

             3x - 4y = -12

the answer will be the last one