To get from his high school to his home, Jamal travels 9 miles east and 9 miles north. When Sheila goes to her home from the same high school, she travels 4 miles east and 5 miles south. What is the distance between Jamal's home and Sheila's home?

14 miles north 5 miles east

Step-by-step explanation:

-5miles 9+5 because distance cant be negitive.

14.6 miles

Step-by-step explanation:

Jamal will end up about \sqrt{162} from the school and Sheila will be about \sqrt{41}. They will be \sqrt{212} for each other or 14.6 miles.

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet