Find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the largest number

x+(x+2) = 3(x+4) -27

Step-by-step explanation:

Let's look at all the parts.

Consecutive odd integers... that means that if x is the first one, then x+2 will be the next largest one, and x+4 will be the largest one.  So if x is 5, x+2 is 7, and x+4 is 9.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0