What is the equation of the line that passes through the point (-1,4) and has a slope of -5?

y = -5x - 1

Step-by-step explanation:

Since you have the slope and a given point you can use the point-slope formula to solve for the y-intercept formula.

Point slope formula = y - y = m(x - x)

m = -5    (-1, 4)

y - 4 = -5(x +1)

y - 4 = -5x - 5

y = -5x - 1

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

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step-by-step explanation: