Mathematics, 11.10.2020 17:01 OzzyDaGod
\begin{cases}b(1)=16 b(n)=b(n-1)+1 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ b(1)=16 b(n)=b(n−1)+1 Find the 2^{\text{nd}}2 nd 2, start superscript, start text, n, d, end text, end superscript term in the sequence.
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\begin{cases}b(1)=16 b(n)=b(n-1)+1 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ b(1)=16 b(n)=b(n−1)+1 Find the 2^{\te...
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