Given the polynomial f(x)=3x3−4x2−3x−1, what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a?

answer: y = 3/2 x - 3

y = 1/8 x - 3/4 that would be your correct option

step-by-step explanation: w

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches