PLEASE HELP I BEG 70 POINTS Part A: Explain how to sketch the graph of a curve that opens downwards and has only one x-intercept at (2.5,0).

Part B: Explain how to sketch the graph of a curve that opens upwards where the minimum value of the graph is (0,1).

Part C: Explain how to sketch the graph of a curve with the following characteristics.
• The graph opens downward.
• The y-intercept is (0,6).
The z-intercepts are (-1,0) and (3, 0).
• The maximum value of the function is located at the point (1,8).

Part A:

If a quadratic has only one x-intercept, then that is where the vertex lies. being that the vertex is the highest or lowest point in the quadratic. To sketch, it will open downwards with a single x-cept

Part B:

The graph will be above the x-axis. And having the vertex being at (0,1) as it says its the minimum value. All the minimum means is that its the lowest value of this given parabola.

Part C:

Plot the points of the y-intercept and z-intercepts. Then plot the maximum value is. Connect the dots.

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)