Kyla alternates between walking and jogging on an 11-mile trail. Her walking speed is 4 mi/h, and her jogging speed is 6 mi/h. Kyla takes 2 hours to go from the beginning to the end of the trail. Write and solve an equation to find the distance Kyla walked and the distance she jogged.

Kyla walked 2 miles and jogged 9 miles

Step-by-step explanation:

Let the distance Kyla walked be x

and the distance Kyla jogged be y

Since the trail is 11-mile long, then

x + y = 11

Now, from the question,

Her walking speed is 4 mi/h and her jogging speed is 6 mi/h

Let the time spent to walk be t₁ and the time spent to jog be t₂

From

Distance = Speed × Time

Then, the distance walked x is

x = 4 mi/h × t₁

and the distance jogged y is

y = 6 mi/h × t₂

From the question, Kyla takes 2 hours to go from the beginning to the end of the trail, that is

t₁ + t₂ = 2 hours

∴t₁ = 2 - t₂

Since

x + y = 11, then we can write that

(4 mi/h × t₁) + (6 mi/h × t₂) = 11

But t₁ = 2 - t₂

Then,

(4 mi/h × t₁) + (6 mi/h × t₂) = 11; becomes

(4 mi/h × (2 - t₂)) + (6 mi/h × t₂) = 11

8 - 4t₂ + 6t₂ = 11

2t₂ = 11 - 8

2t₂ = 3

t₂ = 3/2

t₂ = 1.5 hours

This is the time spent to jog

Then, from t₁ = 2 - t₂

t₁ = 2 - 1.5

t₁ = 0.5 hour

This is the time spent to walk

Now, For the distance Kyla walked, x

x = 4 mi/h × t₁

x = 4 mi/h × 0.5

x = 2 miles

Hence, she walked 2 miles

and for the distance Kyla jogged, y

y = 6 mi/h × t₂

y = 6 mi/h × 1.5

y = 9 miles

Hence, she jogged 9 miles

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

its a trick question

step-by-step explanation:

dogs love water, just turn on the hose and it will run in circles chasing the water all day : )