| 2 +r | ≥ 3 (lines are absolute value)

r ≤ -5 and r ≥ 1

Step-by-step explanation:

The solution has two parts:

1) that derived from | 2 +r | ≥ 3 when (2 + r) is already positive.  Then:

                   2 + r ≥ 3, or r ≥ 1

and

that derived from | 2 +r | ≥ 3 when (2 + r) is negative.  If (2 + r) is negative, then

|(2 + r)| = -(2 + r) = -2 -r, which is ≥ 3.  Therefore, -2 -r ≥ 3, or -r ≥ 5.  To solve this for r, divide both sides by -1 and reverse the direction of the inequality sign:  r ≤ -5

yes

step-by-step explanation:

6e14 is the answer.