A scientist needs 10 liters of a 20% acid solution for an experiment, but she has only a 5% solution and a 40% solution. To the nearest tenth of a liter, about how many liters of the 5% and the 40% solutions should she mix to get the solution she needs? Write and slove an equation to match the situation. : Equation:

Solution: liters of 5% and liters of 40%

Equation: X × 0.4 + (10 - X)×0.05 = 10 × 0.2

Solution: 5.71 liters of 5% and 4.29 liters 40%

Step-by-step explanation:

The volume of the 20% acid solution the scientist needs = 10 liters

The concentration of the solution she has = 5% and 40%

Therefore, we have;

X volume of the 40% solution is mixed with 10 - X volume of the 5% solution, to obtain 10 liters of the 20% solution

Therefore, we have;

Equation: X × 0.4 + (10 - X)×0.05 = 10 × 0.2

0.4·X + 0.5 - 0.05·X = 2

0.35·X = 2 - 0.5 = 1.5

X = 1.5/0.35 = 30/7

∴ The volume of the 40% solution = 30/7 liters ≈ 4.29 liters

The volume of the 5% solution = 10 - X = 10 - 30/7 = 40/7 liters ≈ 5.71 liters

Therefore, we have;

5.71 liters of 5% solution and 4.29 liters 40% solution.

$35.59 in pounds

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.