Two cars travel at the same distance. The first car travel at 50 miles per hour and reaches its destination at t hours. The second car travels at a rate of 60 miles per hour and reaches its destination 1 hour earlier than the first car how long does it take for the first car to reach its destination

It would take the first car 6 hours to reach its destination.

Speed is the ratio of distance to time. It is given by:

Speed = distance /time

Since the two cars travel at the same distance, let d represent this distance.

The first car travel at 50 miles per hour and reaches its destination at t hours. Hence:

50 = d / t

d = 50t   (1)

The second car travels at a rate of 60 miles per hour and reaches its destination 1 hour earlier than the first car. Hence the time = t - 1. Hence:

60 = d / (t - 1)

d = 60(t - 1)

d = 60t - 60   (2)

Equating both equations gives:

50t = 60t - 60

10t = 60

t = 6 hours

Hence it would take the first car 6 hours to reach its destination

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The first car reaches its destination in 6 hours.

Step-by-step explanation:

Speed of the first car = 50 miles per hour

Time taken = t hours

Distance travelled = Speed × Time = 50 t

Speed of the second car = 60 miles per hour

Time taken = hours

Distance travelled = Speed × Time =

As two cars travel the same distance,

So, the first car reaches its destination in 6 hours.

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: