A car increases, then decreases, its speed. Which table could represent the speed of the car? A 2-column table with 5 rows. The first column is labeled time (minutes) with entries 5, 6, 7, 8, 9. The second column is labeled speed (miles per hour) with entries 45, 43, 41, 42, 43. A 2-column table with 5 rows. The first column is labeled time (minutes) with entries 5, 6, 7, 8, 9. The second column is labeled speed (miles per hour) with entries 45, 47, 49, 48, 47. A 2-column table with 5 rows. The first column is labeled time (minutes) with entries 5, 6, 7, 8, 9. The second column is labeled speed (miles per hour) with entries 45, 45, 45, 43, 41. A 2-column table with 5 rows. The first column is labeled time (minutes) with entries 5, 6, 7, 8, 9. The second column is labeled speed (miles per hour) with entries 45, 43, 41, 41, 41.

The speed increases (45—>47—>49) then decreases (48—>47) over time.

Step-by-step explanation:

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∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

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step-by-step explanation:

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