Calculate the mean ,median, or mode of a distribution. There are 10 bags containing tickets numbered 1 to 20. Ten students draw a ticket from each bag. One student drew tickets with the numbers. 5,8,18,1,14,6,8,13,8,19 what would be the correct mean, median, and mode

Step-by-step explanation:

Mean = sum of variables/sample size

Sum of variables = 5+8+18+1+14+6+8+13+8+19

Sum of variables = 100

Sample size = 10

Mean = 100/10

Mean = 10

Median is the value at the centre after rearrangement.

On rearrangement

1,5,6,8),8,8,(13,14,18,19

Median = 8+8/2

Median = 16/2

Median = 8

Mode is the value with the highest frequency. The value that occur the most. From the datas, the mode is 8 since it occurred 3 times.

5

step-by-step explanation:

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all