between 9 p. m. and 6:36 a. m., the water level in a swimming pool decreased by 6/25. assuming that the water level decreased at a constant rate, how much did the water level drop each hour?

The hourly drop between the two times is 1/40

Step-by-step explanation:

Firstly, we need to find the difference in time between 9 pm and 6:36 am

That would be 9 hours and 36 minutes

It would be needed to convert 36 minutes to hours

Mathematically, 60 minutes = 1 hour

So 36 minutes = (36 * 1)/60 = 36/60 = 0.6

So the difference between the two time is simple 9.6 hours

So the total drop during the time is given by 6/25

So the hourly drop will be 6/25 divided by 9.6

= 6/25 * 1/9.6 = 6/240 = 1/40

step-by-step explanation:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!