Someone help me with math please.

hypotenuse² = b² + h²

x² = b² + h²

=> x² = 6² + 4²

=> x² = 36 + 16

=> x² = 52

=> x = √52

=> x = 7.21

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

do your own work and don"t cheat.

step-by-step explanation: