Pb 4 A Bicycle shop assembles bicycles and unicycles. The bikes need 2 wheels, require 4 hours of labor to assemble, and bring
in 300$ or profit. The unicycles only need 1 wheel, require 1 hour of labor, and generate 100$ of profit. The shop has 60
wheels on hand and 80 hours of available labor. The owner wishes to maximize profit on the assumption that he can sell
all the units he assembles.
Let B = number of bikes to be assembled & is constrained by B>=0
Let U = number of unicycles to be assembled & is constrained by U>=0

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!

angle efh= angle egh

the cost of the pair of pants is $31.95