Hexagon IJKLMN is shown on the coordinate plane below: hexagon IJKLMN on a coordinate plane with ordered pairs at I negative two, six, at J four, four, at K six, negative one, at L negative one, two, at M negative four, negative four, and at N negative six, two

If hexagon IJKLMN is dilated by a scale factor of two fifths from the origin to create hexagon I'J'K'L'M'N', what is the ordered pair of point I'?

(−0.8, 2.4)
(−5, 15)
(−2.5, 5)
(−0.4, 0.8)

i will take them

step-by-step explanation:

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb