The point P(-2, - 5) is rotated 90° about the origin, and then the image is reflected across the line x= 3. What are the coordinates of the final image p’’?

Given:

The point P(-2, - 5) is rotated 90° about the origin, and then the image is reflected across the line  x= 3.

To find:

The the coordinates of the final image P’’.

Solution:

The point P(-2, - 5) is rotated 90° about the origin. It means the point is rotated 90° counter clockwise about the origin

Then the image is reflected across the line  x= 3.

Therefore, the \coordinates of the final image P'' are (1,-2).

1010: 3030

is it i think

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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