given cos θ= √35/6 and angle θ is in Quadrant I, what is the exact value of sin θ in simplest form? Simplify all radicals if needed.

Here, I've attached a picture of the triangle that accompanies this explanation.

cot = = =

Now view the triangle.

PS. Angle theta will have a coordinate of (-, +) because it is in quadrant II.

sin of the angle would be opposite/hypotenuse, so sin =

cos of the angle would be adjacent/hypotenuse, so cos =

tan of the angle would be opposite/adjacent, so tan =

it has the same slope and a different y-intercept

hope this : )