Which equation is the slope-intercept form of the equation of the line that passes through (1, 2) and is parallel to 4x - 2y = 6?

The equation of the parallel line is y = 2x  

Step-by-step explanation:

The slope-intercept form of the linear equation is:

y = m x + b, where

Parallel lines have the same slopes and different y-intercepts

∵ The equation of the given line is 4x - 2y = 6

→ To find the slope of this line re-arrange it to be in the

   slope-intercept form Subtract 4x from both sides to move x to

   the right side

∵ 4x - 4x - 2y = 6 - 4x

∴ -2y = 6 - 4x

→ Divide both sides by -2 to make the coefficient of y = 1

∵

∴ y = -3 - (-2x)

∴ y = -3 + 2x

→ Swithch -3 and 2x

∴ y = 2x - 3

→ Compare it by the form of the equation above to find m

∴ m = 2

∴ The slope of the given line is 2

∵ The two lines are parallel

∴ The slope of the parallel line is 2

→ Substitute it in the form of the equation above

∴ y = 2x + b

→ To find b substitute x and y in the equation by the coordinates

   of any point on the line

∵ The line passes through the point (1, 2)

∴ x = 1 and y = 2

∵ 2 = 2(1) + b

∴ 2 = 2 + b

→ Subtract 2 from both sides to find b

∴ 2 - 2 = 2 - 2 + b

∴ 0 = b

∴ y = 2x

The equation of the parallel line is y = 2x    

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

step-by-step explanation: