Write the equation of a line that is perpendicular to y=-2/7x+9 and that passes through the point (4,-6)

y = 7/2x - 20

Step-by-step explanation:

The slope of a perpendicular line is the opposite reciprocal of the original slope.

-2/7 -> 7/2

Find the new y-intercept.

y = 7/2x + b

-6 = 7/2(4) + b

-6 = 14 + b

-20 = b

y = 7/2x - 20

Best of Luck!

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752