Solve for the x in the equation

x=1

Step-by-step explanation:

x+3x+5x+7x+...+49x=625

(1+3+5+7+...+49)x=625    (1)

now consider s= 1+3+5+7+...+49

a=1

d=3-1=2

l=49

l=a+(n-1)d

49=1+(n-1)2

49-1=(n-1)2

48/2=n-1

n-1=24

n=24+1=25

s=n/2*(a+l)

s=25/2(1+49)

x=25/2×50

s=25×25=625

from (1)

625 x=625

x=625/625=1

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)