the first term of a geometric progression is 12 and the second term is -6. Find the (i) the tenth term of the progression (ii) the sum to infinity

Step-by-step explanation:

a1=ar⁰=12 A2=ar¹=-6

a=12 ar=-6

12r=-6

r=-6/12

r=-1/2

a10=ar⁹

=12*(-1/2)⁹

=12*(-512)

=-3/128

S∞ = a1 / (1-r )

=12/(1-1/2)

=12*1/2

=6

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363