The scores of the quizzes of five students in both English and Science are: English Science

Student 1 6 8

Student 2 5 5

Student 3 9 6

Student 4 4 7

Student 5 8 9

For English, the mean is 6.4 and the standard deviation is 2.0. For Science, the mean is 7 and the standard deviation is 1.6. Using the formula below or Excel, find the correlation coefficient, r, for this set of scores. Answer choices are rounded to the nearest hundredth. ram-izlet 0

a) 0.23

b) 0.05

c) 0.50

d) 0.42

0.23

Step-by-step explanation:

Given the data:

(x) __(y)__(x - m1) /s1 ___(y-m2) /s2

1 ___6 ___8__ - 0.2 0.625

2 __5 ___ 5__ - 0.7 - 1.25

3 __96__ 1.3 - 0.625

4__ 4 7__ - 1.2 0

5__ 8 9 _ 0.8 1.25

For English :

Mean score(m1) = 6.4

Standard deviation (s1) = 2.0

For Science :

Mean score (m2) = 7.0

Standard deviation (s2) = 1.6

n = number of observations = 5

Correlation Coefficient (r) :

r = 1/(n - 1) Σ[((X - m1) / s1) * ((Y - m2) /s2)]

(-0. 2 * 0.625) + (-0.7 * - 1.25) + (1.3 * - 0.625) + (-1.2 * 0) + (0.8 * 1.25) = 0.9375

r = 0.9375/(5-1)

= 0.234

= 0.23

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

[2, 2.5)

(2.5, 3]

step-by-step explanation:

i think its these two not sure [2, 2.5)

(2.5, 3]