Megan has 62 rocks in her rock collection. She wants to put 2 rocks in some cases and 11 rocks in other cases. Select a possible arrangement of rocks. A. Have 4 cases of 2 rocks, and 9 cases of 11 rocks. B. Have 9 cases of 2 rocks, and 4 cases of 11 rocks. C. Have 9 cases of 2 rocks, and 1 case of 11 rocks. D. Have 1 case of 2 rocks, and 4 cases of 11 rocks.

. B. Have 9 cases of 2 rocks, and 4 cases of 11 rocks

Step-by-step explanation:

Total rocks = 62

A. Have 4 cases of 2 rocks, and 9 cases of 11 rocks

(4 * 2) + (9 * 11) > 62 ( false)

B. Have 9 cases of 2 rocks, and 4 cases of 11 rocks

(9 * 2) + (4 * 11) = 18 + 44 = 62 rocks (true)

C. Have 9 cases of 2 rocks, and 1 case of 11 rocks

(9 * 2). + (1 * 11) < 62 ( false)

D. Have 1 case of 2 rocks, and 4 cases of 11 rocks.

(1 * 2) + (4 * 11) < 62

answer: a.   one is a factor of every whole number since every number is divisible by itself.