Mathematics, 13.10.2020 03:01 bankskry
The Pythagorean theorem states that the sum of the squares of the legs of a right triangle is equal to the square of the
hypotenuse by the formula a2 + b2 = c2.
If a is a rational number and b is a rational number, why could c be an irrational number?
O The square of rational numbers is irrational, and sum of two irrational numbers is irrational.
O The product of two rational numbers is rational, and the sum of two rational numbers is irrational.
O The left side of the equation will result in a rational number, which is a perfect square.
O The left side of the equation will result in a rational number, which could be a non-perfect square.
Answers: 3
and 
rational numbers whose forms are, respectively:
and 
, 
, 
, 
, 
Given.
1) in 2)
Definition of division.![c^{2} = [m^{2}\cdot (n^{-1})^{2}]+[q^{2}\cdot (r^{-1})^{2}]](/tpl/images/0802/3270/c05a6.png)
![c^{2} = [m^{2}\cdot (n^{2})^{-1}]+[q^{2}\cdot (r^{2})^{-1}]](/tpl/images/0802/3270/f0423.png)
Definition of division.
is a rational number, then 
, so that 
. Which means that 
is an entire number. Another question on Mathematics
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