A structural steel fabricator cuts 25 pieces each 16.2 centimeters long from a 6.35-meter length of channel iron. Allowing 4 millimeters waste for each piece, find the length in meters of
channel iron left after all 25 pieces have been cut.

2.2 meters

Step-by-step explanation:

The data is:

The initial piece is 6.35 meters long.

We cut 25 pieces of 16.2cm each, so in pieces only we have:

25*16.2cm = 405cm

1m = 100cm

Then: 405cm = (405/100) m = 4.05m

And each time that we cut a piece, we have 4mm of waste.

Then we have 25 times the 4mm of waste, this means that the total waste is:

4mm*25 = 100mm

and 1000mm = 1m

100mm = (100/1000) m = 0.1m

So the total amount that was cut is:

4.05m + 0.1m = 4.15m

The length in the channel iron will be: 6.35m - 4.15m = 2.2 meters

table 3 represents a direct variation function. : )

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )