a square with an area of 25 in.^2 is plotted on a grid so that the bottom-left corner is at the origin. The side of the square are horizontal and vertical. A reflection over what line maps the square onto itself?

Reflection about the vertical line x = 2.5 inches will map the square unto itself

Step-by-step explanation:

The given parameters are;

The area of the square = 25 in²

The orientation of the sides of the square are horizontal and vertical

Therefore, we have;

The area, A, of the square given by the following relation;

A = Side²

A = 25 in²

Therefore;

The area of the square = 25 = side²

The length of the sides of the square = √A = √25 = 5

The length of the sides of the square = 5 inches

The reflection of a figure that maps the figure unto itself is a reflection along the line of symmetry

One of the line of symmetry that divides the square into two similar halves is the vertical straight that passes half way through the horizontal side, which is the point 2.5 inches to the right on the x-axis with the coordinates (2.5, 0)

Therefore, reflection about the line x = 2.5 inches will map the square unto itself.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

the first one

step-by-step explanation:

just id the test.