What are the zeros of this quadratic function? AX) = (x-7)(x+8)
ОА.
x=0 and x= -8
OB.
x= 7 and x=-8
Ос.
x= -7 and x= 8
OD.
x= 0 and x=7

B

Step-by-step explanation:

Given

f(x) = (x - 7)(x + 8)

To obtain the zeros , let f(x) = 0, that is

(x - 7)(x + 8) = 0

Equate each factor to zero and solve for x

x - 7 = 0 ⇒ x = 7

x + 8 = 0 ⇒ x = - 8

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents